Question

G(x)= √x+3 help plsss

Answer 1

`\boxed{\mathrm{B}}`

Explanation:

`g(x)=√(x+3)`

A square root must have a value of greater than or equal to 0.

`√(x+3)\geq 0`

Square both sides.

`x+3\geq 0`

Subtract 3 from both sides.

`x\geq -3`

Answer 2

All real values of x such that x ≥-3

Explanation:

g(x) = sqrt(x+3)

A sqrt must be greater than or equal to zero

sqrt (x+3) ≥ 0

Square each side

x+3≥ 0

Subtract 3 from each side

x ≥-3

The restrictions on x are x ≥-3

That means the domain is x ≥-3

All real values of x such that x ≥-3