Answer:
![\large \boxed{\sf \ \ 69 \ \textbf{touchdowns } 11 \ \textbf{field goals } \ }](https://img.qammunity.org/2021/formulas/mathematics/college/52rtrdu1mu1zlzamz6vh0drhoyl7krzebd.png)
Explanation:
Hello,
Touchdown is 7 points, field goals is 3 points
Let's note a the number of touchdowns and b the number of field goals, we can write
(1) a + b = 80
(2) 7a + 3b = 516
(2) - 3*(1) gives
7a + 3b - 3(a + b) = 516 - 3*80
<=> 7a + 3b -3a - 3b = 516 - 240 = 276
<=> 4a = 276
<=>
![a=(276)/(4)=69](https://img.qammunity.org/2021/formulas/mathematics/college/yu6gkvoji2mlxmy226ilcc0mb812pipvm4.png)
And then from (1) b = 80 - 69 = 11
Hope this helps