Question

Which of the following would NOT be a conversion factor for mole to mole calculations for the following reaction: 2Al + 3Cl2 --> 2AlCl3

A: 3 mol Cl2 3 mol Al
B: 2 mol Al 3 mol Cl2
C: 2 mol AlCl3 2 mol Al
D: 3 mole Cl2 2 mol AlCl3

Answer 1

Answer: A. 3 mol
`Cl_2` 3 mol Al:

Step-by-step explanation:

Te given balanced chemical equation is :

`2Al+3Cl_2\rightarrow 2AlCl_3`

According to the stochiometry :

A: 3 mol
`Cl_2` 3 mol Al:

3 moles of chlorine reacts with 2 moles of aluminium

B. 2 mol
`Al` 3 mol
`Cl_2`:

2 moles of aluminium reacts with 3 moles of chlorine

C. 2 mol
`AlCl_3` 2 mol Al

2 mol of aluminium produces 2 mol of
`AlCl_3`

D. 3 mol
`Cl_2` 2 mol
`AlCl_3`

3 moles of chlorine produces with 2 moles of
`AlCl_3`

Thus the conversion factor not used for mole to mole calculations is 3 mol
`Cl_2` 3 mol Al: