Complete Question
The complete question is shown on the first uploaded image
Answer:
The wavelength is
![\lambda= (2 \pi )/(k)](https://img.qammunity.org/2021/formulas/physics/college/b2atd39tly2e6onjqiyvbya1vz2jxxn7m2.png)
Step-by-step explanation:
From the question we are told that
The electric field is
![\= E = E_o sin (kx - wt )\r j](https://img.qammunity.org/2021/formulas/physics/college/wr88xefka8oin1uca3x3j40o6mno7fzkme.png)
The magnetic field is
![\= B = B_0 sin (kx -wt) \r k](https://img.qammunity.org/2021/formulas/physics/college/mq1wbxtay399phs62gquvmcs340b0tx4ys.png)
From the above equation
and k is the wave number which is mathematically represented as
![k = (2 \pi )/(\lambda )](https://img.qammunity.org/2021/formulas/physics/college/1p7gnk3jhkq404a17bnde3m1epl1lsm4jv.png)
=>
![\lambda= (2 \pi )/(k)](https://img.qammunity.org/2021/formulas/physics/college/b2atd39tly2e6onjqiyvbya1vz2jxxn7m2.png)
Where
is the wavelength