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If a solution initially contains 0.260 M HC2H3O2, what is the equilibrium concentration of H3O+ at 25 ∘C? Express your answer in moles per liter to two significant figures. View Available Hint(s)

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Answer:

2.16 × 10⁻³

Step-by-step explanation:

Step 1: Given data

Concentration of the acid (Ca): 0.260 M

Acid dissociation constant (Ka): 1.80 × 10⁻⁵

Step 2: Write the acid dissociation equation

HC₂H₃O₂(aq) + H₂O(l) ⇄ C₂H₃O₂⁻(aq) + H₃O⁺(aq)

Step 3: Calculate the concentration of H₃O⁺ at equilibrium

We will use the following expression.


[H_3O^(+) ]= √(Ka * Ca ) = \sqrt{1.80 * 10^(-5) * 0.260 } = 2.16 * 10^(-3)

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