Answer:
2.16 × 10⁻³
Step-by-step explanation:
Step 1: Given data
Concentration of the acid (Ca): 0.260 M
Acid dissociation constant (Ka): 1.80 × 10⁻⁵
Step 2: Write the acid dissociation equation
HC₂H₃O₂(aq) + H₂O(l) ⇄ C₂H₃O₂⁻(aq) + H₃O⁺(aq)
Step 3: Calculate the concentration of H₃O⁺ at equilibrium
We will use the following expression.
![[H_3O^(+) ]= √(Ka * Ca ) = \sqrt{1.80 * 10^(-5) * 0.260 } = 2.16 * 10^(-3)](https://img.qammunity.org/2021/formulas/chemistry/college/m81d2171msk22my90h6jvverusk80gs6k4.png)