Question

Find two numbers in a given ratio such that the difference of their squares is to the sum of the numbers in a given ratio.Ratios, respectively, are 3 to 1 and 6 to 1.

Answer 1

According to the given situation, the computation of two number in a given ratio is shown below:-

We assume the numbers is x and y

Given that

`(x)/(y) = (3)/(1)`

x = 3y

and

`(x^2-y^2)/(x + y) = (6)/(1) \\\\((x + y) (x - y))/((x + y)) = 6`

With the help of above formula we will put the value and be able to find the values of x and y

x - y = 6

3y - y = 6

2y = 6

y = 3

x = 3y = 9

x = 9, y = 3

Therefore the correct answer is x = 9 where as y = 3