Question

If you combine 24.2 g of a solute that has a molar mass of 24.2 g/mol with 100.0 g of a solvent, what is the molality of the resulting solution

Answer 1

Answer: 10 moles/kg.

Step-by-step explanation:

Given, Mass of solute = 24.2 g

Molar mass of solute = 24.2 g/mol

`\text{Moles of solute =}\frac{\text{Mass of solute}}{\text{Molar mass of solute}}\\\\=(24.2)/(24.2)=1`

Mass of solvent = 100.0g = 0.1 kg [1 g=0.001 kg]

`\text{Molality}=\frac{\text{Moles of solute}}{\text{kilograms of Solvent}}\\\\=(1)/(0.1)\\\\=10\ moles/kg`

Hence, the molality of the resulting solution is 10 moles/kg.