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A physics professor uses an air-track cart of mass m to compress a spring of constant k by an amount x from its equilibrium length. The air-track has negligible friction. When she lets go, the spring launches the cart. What cart velocity should she expect after it is launched by the spring

User Sadek
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1 Answer

1 vote

Answer:

v = √k/m x

Step-by-step explanation:

We can solve this exercise using the energy conservation relationships

starting point. Fully compressed spring

Em₀ =
K_(e) = ½ k x²

final point. Cart after leaving the spring


Em_(f) = K = ½ m v²

Em₀ = Em_{f}

½ k x² = ½ m v²

v = √k/m x

User Mmssaann
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