Answer:
A) the probability of winning is 0.24%.
B) Yes i will play the game
C) Despite the fact that the probability of winning is very low, one should play the game because the expected value of the game is positive.
Explanation:
Expected value of X is denoted by;
E(X) = x1•p1 + x2•p2 +..... xn•pn
Where;
xi is the observation and pi is the probability of xi
Now, let's make p the probability of the winning bet and 1 - p be the probability of losing the game
If the bet is win, the net gain is $98,800 and if the bet is lose, the loss is -$1200.
Hence the probability distribution will be;
For xi = $98,800, pi = p
For xi = -$1,200, pi = 1 - p
So;
E(X) = Σxi.pi
Thus;
1200 = 98800p - 1200(1 - p)
1200 = 98800p - 1200 + 1200p
1200 + 1200 = 100000p
2400 = 100000p
p = 2400/100000
p = 0.024
Thus, the probability of winning is 0.24%.
Despite the fact that the probability of winning is very low, one should play the game because the expected value of the game is positive.