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An alternating source drives a series RLC circuit with an emf amplitude of 6.34 V, at a phase angle of +32.6°. When the potential difference across the capacitor reaches its maximum positive value of +5.08 V, what is the potential difference across the inductor (sign included)?

User Nitza
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1 Answer

5 votes

Answer:

V=-8.35v

Step-by-step explanation:

Pls see attached file

An alternating source drives a series RLC circuit with an emf amplitude of 6.34 V-example-1
An alternating source drives a series RLC circuit with an emf amplitude of 6.34 V-example-2
User Cbas
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