Question

An electromagnetic ware has a maximum magnetic field strength of 10^-8 T at a specific place in vacuum. What is the intensity of the light at that place. μ0=4πx10^-7 WbA/m g

Answer 1

`I=1.19* 10^(-2)\ W/m^2`

Step-by-step explanation:

It is given that,

Maximum value of magnetic field strength,
`B=10^(-8)\ T`

We need to find the intensity of the light at that place.

The formula of the intensity of magnetic field is given by :

`I=(c)/(2\mu _o)B^2`

c is speed of light

So,

`I=(3* 10^8)/(2* 4\pi * 10^(-7))* (10^(-8))^2\\\\I=1.19* 10^(-2)\ W/m^2`

So, the intensity of the light is
`1.19* 10^(-2)\ W/m^2`.