Question

DatGuy323! Sekkrit! U there? Find the factors of
x^2 + 7x + 6 = 0

Answer 1

`x=-1,\:x=-6`

Explanation:

We can solve this question by applying a quadratic equation, but it would be easier to simply factor the equation. In other words, let's begin by factoring the expression
`x^2` + 7x + 6,

Break this expression down into groups -
`\left(x^2+x\right)+\left(6x+6\right)`,

Factor out x from "
`\left(x^2+x\right)` " =
`{\quad }x\left(x+1\right)`,

Respectively factor out 6 from "
`6x+6\mathrm{}` " =
`6\left(x+1\right)`,

`x\left(x+1\right)+6\left(x+1\right)` - and now we can group like terms -
`\left(x+1\right)\left(x+6\right)`

Since we have factored this expression, let's make it equivalent to 0, and solve for x. By the Zero Factor Principle we should receive two solutions,

`\left(x+1\right)\left(x+6\right)=0`,

`x+1=0: x=-1` /
`x+6=0: x=-6`,

The solutions to this equation should thus be :
`x=-1,\:x=-6`

Answer 2

Answer: x = -6, -1

Explanation:

Factor

(x+6)(x+1)=0

To get 0 out of multiplication, you must have one term equal 0. Thus, either x+6 or x+1 must equal 0. Thus, x = -6,-1

Hope it helps <3

tyvm :)