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For the inequality y+4x≤x2+2, where is the graph shaded and is the curve solid or dotted?

User Leton
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1 Answer

4 votes

Answer:

The graph shaded outside the parabola and the curve is solid.

Explanation:

The given inequality is


y+4x\leq x^2+2

It can be rewritten as


y\leq x^2-4x+2

The sign of inequality is
\leq, so the curve is a solid line.

The related equation of line is


y=x^2-4x+2

Table of values is

x 0 2 4

y 2 -2 2

Plot these points and draw a U-shaped curve.

Check the equality for (0,0).


0\leq (0)^2-4(0)+2


0\leq 2

This statement is true. So, (0,0) lies in the shaded portion.

So, shade the graph outside the parabola.

For the inequality y+4x≤x2+2, where is the graph shaded and is the curve solid or-example-1
User Esaj
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6.2k points