Answer:
QUESTION①)
✔ First step : calculate the kinetic energy that this car requires to reach 95 km/h
95/ 3,6 ≈ 26,4 m/s
Ec = ½ m x V²
With Ec in J; m in kg; and V in m/s
- Ec = ½ 1750 x 26,4²
- Ec ≈ 610 000 J
✔ Knowing that the car has a p power of 215,000 W, so :
T = E/P
- T = 610 000/215 000
- T ≈ 2.8 s
The car takes 2.8 s to reach 95 km/h
QUESTION②)
N = 2,8/6,5 x 100 = 43.07
The car efficiency is 43 %