Question

asked Oct 1, 2021 215k views

2 Answers

Douglas Adams · Answer 1 · 2021-10-03T16:45:23+0000

Answer:

$x=5\\y=2$

Explanation:

x^2 +y^2 =29

x+y=7

Solve for x in the second equation.

x+y=7

x+y-y=7-y

x=7-y

Plug in the value for x in the first equation and solve for y.

(7-y)^2 +y^2 =29

y^2-14y+49+y^2 =29

2y^2-14y+20=0

2(y-2)(y-5)=0

$2(y-2)=0\\y-2=0\\y=2$

$y-5=0\\y=5$

y<4

y=2

$y\\eq 5$

Plug y as 2 in the second equation and solve for x.

x+y=7

x=7-y

x=7-2

x=5

Veight · Answer 2 · 2021-10-08T18:25:32+0000

Answer: :o I FINALLY MADE IT

(5, 2)

x = 5

y = 2

Explanation:

First, I graphed both equations. They meet at the points (5,2) and (2,5). Because y < 5, the solution is (5, 2)

Hope it helps <3

$Datguy323 is going to complain again. What's the variables for: x^2+y^2=29\\x+y=7 y-example-1$

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