Question

Who'd be better at speed answering? Datguy323 or some Helping Hand? (Not a serious question) Solve for the variables:
`x^3+y^7=28\\x^3=27`

Answer 1

Answer: (3,1)

Explanation:

First, to find x, simply take the cube root of 27, or 3. Thus, x = 3.

Then, simply plug it in:

`27+y^7=28\\Subtract(27)\\y^7=1\\y=1`

Thus, y = 1

Hope it helps <3

p.s. for some reason, in a graphing calculator, it shows no solutions

Hope it helps <3

2 in a row!

Answer 2

x = 3

y = 1

Explanation:

The equations are:

`x^3+y^7 = 28`

and

`x^3 = 27`

Putting second equation in the first one:

=>
`27+y^7 = 28`

Subtracting 27 to both sides

=>
`y^7 = 28-27`

=>
`y^7 = 1`

Taking power 7 to both sides

=> y = 1

Now,

`x^3 = 27`

Taking cube root on the both sides

x = 3