Question

A circle has a radius of 6/7 units and is centered at (-2.3,0) What is the equation of the circle

Answer 1

(x+2.3)^2 + (y) ^2 = (6/7)^2

Explanation:

The equation of a circle can be written as

(x-h)^2 + (y-k) ^2 = r^2 where ( h,k) is the center and r is the radius

(x- -2.3)^2 + (y-0) ^2 = (6/7)^2

(x+2.3)^2 + (y) ^2 = (6/7)^2