Question

Suppose I have a circular loop of wire with radius R. I run a current I through the loop and measure a magnetic field B at the center of the wire. If I double the radius of the wire and triple the current in the wire, what is the new magnetic field at the center of the wire

Answer 1

Step-by-step explanation:

The magnetic field at the center of the wire is given by :

`B=(\mu_oI)/(2r)`

Here,

I is current flowing throgh the loop

r is the radius of loop

If the radius of the wire is doubled and the current is tripled, then new magnetic field is given by :

`B'=(\mu_oI')/(2r')\\\\B'=(\mu_o(3I))/(2(2r))\\\\B'=(3)/(2)* (\mu_oI)/(2r)\\\\B'=(3)/(2)* B`

So, the new value of magnetic field gets 3/2th of the initial magnetic field.