Question

Hi again here's the picture

Answer 1

351.88 m²

Explanation:

diameter of the semicircle=42 the radius=42/2=21

perimeter of circle=2π r=2(3.14(21))= 131.88(since you have two semi-circle,then it is a full circle)

perimeter of the rectangle: 2(110)=220( the width used to measure the perimeter of the circle)

the area of the track=131.88+220=351.88

Answer 2

351.88 m

Explanation:

Given,

D = diameter of semicircular part = 42 m

L = Length of straight part = 110 m

Now, let's find the perimeter:

= 2 ( length of semi-circle + length of straight part )

`= 2( (\pi \: d)/(2) + l)`

Plug the values

`= 2( (3.14 * 42)/(2) + 110)`

Calculate the product

`= 2( (131.88)/(2) + 110)`

Divide

`= 2 (65.94 + 110)`

Calculate the sum

`= 2 * 175.94`

Calculate

`= 351.88 \: m`

Hope this helps..

Best regards!!