Question

What distance does a mobile travel that with a constant acceleration of 3m / s increases its speed from 6m / s to 12m / s

Answer 1

18 m

Step-by-step explanation:

Given:

v₀ = 6 m/s

v = 12 m/s

a = 3 m/s²

Find: Δx

v² = v₀² + 2aΔx

(12 m/s)² = (6 m/s)² + 2 (3 m/s²) Δx

Δx = 18 m