90.5k views
3 votes
An optical fiber uses one glass clad with another glass. What is the critical angle? (Assume the glass in the fiber has an index of refraction of 1.69, and the glass in the cladding has an index of refraction of 1.50.)

1 Answer

0 votes

Answer:

The critical angle is
\theta _c = 62.57^o

Step-by-step explanation:

From the question we are told that

The index of refraction of the glass in the fiber is
n_f = 1.69

The index of refraction of the glass in the cladding is
n_c = 1.50

The critical angle is mathematically evaluated as


\theta_c = sin^(-1)[(n_c )/(n_f ) ]

substituting values


\theta_c = sin^(-1)[(1.50 )/(1.69 ) ]


\theta _c = 62.57^o

User Justlike
by
7.8k points