Question

1. Find the sum of the first five (5) terms of the arithmetic progression
60 + 91 +122 ---.​

Answer 1

Answer: 610

Explanation:

This sequence starts at 60 and increases by increments of 31. Thus, to get the last two numbers, do 122+31=153, and 153+31=184. Then add 60+91+122+153+184 to get 610.

Hope it helps <3

Answer 2

Explanation:

to find the sum of nth term

equation is

n/2 ( 2a + (n-1)d) where a is the 1st term and d is the common difference

5/2 ( 120 +( 4 × 31))

5/2 ( 120 + 124)

5/2 × 244

5 × 122 dividing 244 by 2

610