Question

Calculate the amount of heat energy, in kJ, needed to increase the temperature of 200g of water by 300 C.

Answer 1

Q = 246 kJ

Step-by-step explanation:

It is given that,

Mass of water, m = 200 g

Let initial temperature,
`T_i=5^(\circ)`

Final temperature of water,
`T_f=300^(\circ) C`

We know that the specific heat capacity of water,
`c=4.18\ J/g-^(\circ) C`

So, the heat energy needed to raise the temperature is given by :

`Q=mc\Delta T\\\\Q=200* 4.18* (300-5)\\\\Q=246620\ J`

or

Q = 246 kJ

So, the heat energy of 246 kJ is needed.