Question

Determine the points of intersection of the equation circumference x² + (y-3) ² = 25 with the coordinate axes.

Answer 1

`x^2 +(y-3)^2 = 25`

And we want to find the coordinate axes so then we can do the following:

If x=0 we have:

`0^2 +(y-3)^2 = 25`

`(y-3)^2= 25`

`y-3= \pm 5`

`y_1 = 5+3=8`

`y_2 = -5+3=-2`

Now of y =0 we have:

`x^2 +9 = 25`

`x^2 = 16`

`x= \pm 4`

And then the coordinate axes are:

(4,0) (-4,0), (0,8), (0,-2)

Explanation:

For this cae we have the following functon given:

`x^2 +(y-3)^2 = 25`

And we want to find the coordinate axes so then we can do the following:

If x=0 we have:

`0^2 +(y-3)^2 = 25`

`(y-3)^2= 25`

`y-3= \pm 5`

`y_1 = 5+3=8`

`y_2 = -5+3=-2`

Now of y =0 we have:

`x^2 +9 = 25`

`x^2 = 16`

`x= \pm 4`

And then the coordinate axes are:

(4,0) (-4,0), (0,8), (0,-2)