Question

Help, please!!! What is the mN?

Answer 1

61°

Explanation:

Given:

∆MNO,

Side MO (n) = 18

MN (o) = 6

m<O = 17°

Required:

m<N

Solution:

Using the sine rule,
`(sin N)/(n) = (sin O)/(o)` , solve for N.

Plug in the values of M, n, and m

`(sin N)/(18) = (sin 17)/(6)`

Cross multiply

`6*sin(N) = sin(17)*18`

`6*sin(N) = 0.292*18`

Divide both sides by 6

`(6*sin N)/(6) = (0.292*18)/(6)`

`sin N = (0.292*18)/(6)`

`sin N = (5.256)/(6)`

`sin N = 0.876`

`N = sin^-1(0.876)`

`N = 61.16`

m<N ≈ 61°