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What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12? (–∞, –3] [–3, ∞) (–∞, 15] [15, ∞) SORRY THIS IS THE FULL QUESTION

User Opedge
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1 Answer

5 votes

Answer:

[15, ∞).

Explanation:

–3(6 – 2x) ≥ 4x + 12

-18 + 6x ≥ 4x + 12

6x - 4x ≥ 12 + 18

2x ≥ 30

x ≥ 15

This means that the minimum of x is 15, and the most is infinity, which is the same thing as [15, ∞).

Hope this helps!

User Yansi
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