Answer:
The answers to your questions are given below.
Explanation:
Data obtained from the question include:
Opposite = b
Adjacent = a
Hypothenus = c
Sin θ =..?
Cos θ =.. ?
Tan θ =..?
A. Determination of Sin θ
Sin θ = Opposite /Hypothenus
Opposite = b
Hypothenus = c
Sin θ = Opposite /Hypothenus
Sin θ = b/c
B. Determination of Cos θ
Cos θ = Adjacent / Hypothenus
Adjacent = a
Hypothenus = c
Cos θ = Adjacent / Hypothenus
Cos θ = a/c
C. Determination of Tan θ.
Tan θ = Opposite/ Adjacent
Opposite = b
Adjacent = a
Tan θ = Opposite/ Adjacent
Tan θ = b/a
D. Simplification of Sin θ = Cos(90 – θ)
Recall:
Cos (A – B) = CosACosB + SinASinB
Cos(90 – θ) = Cos90Cosθ + Sin90Sinθ
Therefore,
Sin θ = Cos(90 – θ)
Sin θ = Cos90Cosθ + Sin90Sinθ
But:
Sin θ = b/c
Cos 90 = 0
Cos θ = a/c
Sin 90 = 1
Sin θ = Cos90Cosθ + Sin90Sinθ
b/c = 0 x a/c + 1 x b/c
b/c = b/c