Answer:
94.248 g/sec
Step-by-step explanation:
For solving the total current of the blood passing first we have to solve the cross sectional area which is given below:
![A_1 = \pi R^2\\\\A_1 = \pi (1)^2\\\\A_1 = 3.1416 cm^2](https://img.qammunity.org/2021/formulas/physics/college/8c8zqawrr1wq4sfn0ikjmr4jve6jj4nk0j.png)
And, the velocity of blood pumping is 30 cm^2
Now apply the following formula to solve the total current
![Q = \rho A_1V_1\\\\Q = (1)(3.1416)(30)\\\\](https://img.qammunity.org/2021/formulas/physics/college/vgs5zhrizx0am339e9hr7tcvkcuoxq7wcb.png)
Q = 94.248 g/sec
Basically we applied the above formula So, that the total current could come