Answer:
68.9 g of KCN.
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
KCN + HCl → KCl + HCN
From the balanced equation above,
1 mole of KCN reacted with 1 mole of HCl.
Next, determination of the number of mole of KCN needed to react with 1.06 moles HCl.
This is illustrated below:
From the balanced equation above,
1 mole of KCN reacted with 1 mole of HCl.
Therefore, 1.06 moles of KCN will also react with 1.06 moles of HCl.
Finally, we shall convert 1.06 moles of KCN to grams.
This can be obtained as follow:
Molar mass of KCN = 39 + 12 + 14 = 65 g/mol.
Mole of KCN = 1.06 moles
Mass of KCN =...?
Mole = mass /Molar mass
1.06 = mass of KCN / 65
Cross multiply
Mass of KCN = 1.06 x 65
Mass of KCN = 68.9 g
Therefore, 68.9 g of KCN is needed to react with 1.06 moles of HCl.