Question

9.

A 0.060 kg tennis ball hits the wall horizontally. The moment the ball hits the wall it accelerates at a rate of – 752 m/s2. What is the force that the ball applied to the wall?​

Answer 1

The force applied by the tennis ball to the wall is -45.12 N.

Step-by-step explanation:

When a tennis ball hits a wall, it exerts a force on the wall, known as the force of impact. This force can be calculated using Newton's second law of motion, which states that force is equal to the mass of an object multiplied by its acceleration. In this case, the mass of the tennis ball is 0.060 kg and its acceleration is -752 m/s² (negative sign indicating acceleration in the opposite direction). Therefore, the force applied by the ball to the wall can be calculated as:

Force = mass x acceleration

Force = 0.060 kg x -752 m/s²

Force = -45.12 N

The force applied by the ball to the wall is -45.12 N.