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The voltage and power ratings of a particular light bulb, which are its normal operating values, are 110 V and 60 W. Assume the resistance of the filament of the bulb is constant and is independent of operating conditions. If the light bulb is operated at a reduced voltage and the power drawn by the bulb is 36 W. What is the operating voltage of the bulb?

a. 78 V
b. 72 V
c. 66 V
d. 90 V
e. 85 V

User Dadadima
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1 Answer

5 votes

Answer:

c. 66 V

Step-by-step explanation:

p =IV

I =P/V

P1/V1=P2/V2

60/110=36/V2

0.55 = 36/V2

V2 =36/0.55 = 65.5V

V2 = 66V

User Quickmute
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