Question

PLZ HELP This is due today and if I don’t finish I fail

Answer 1

`x=12,\:y=6`

Explanation:

`\begin{bmatrix}(2)/(3)x+3y=26\\ 2x+(1)/(2)y=27\end{bmatrix}`

`(2)/(3)x+3y=26`

`(2)/(3)x+3y-3y=26-3y`

`(2)/(3)x=26-3y`

`3\cdot (2)/(3)x=3\cdot \:26-3\cdot \:3y`

`2x=78-9y`

`(2x)/(2)=(78)/(2)-(9y)/(2)`

`x=(78-9y)/(2)`

`\begin{bmatrix}2\cdot (78-9y)/(2)+(1)/(2)y=27\end{bmatrix}`

`\begin{bmatrix}78-(17)/(2)y=27\end{bmatrix}`

`78-(17)/(2)y=27`

`78-(17)/(2)y-78=27-78`

`-(17)/(2)y=-51`

`2\left(-(17)/(2)y\right)=2\left(-51\right)`

`-17y=-102`

`(-17y)/(-17)=(-102)/(-17)`

`y=6`

`x=(78-9\cdot \:6)/(2)`

`x=12`

`x=12,\:y=6`

Answer 2

The solution ( 12,6) is correct, Lizette's solution