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A fan blade, initially at rest, rotates with a constant acceleration of 0.029 rad/s2. What is the time interval required for it to reach a 6.58-rad displacement after starting from rest

User Ben Miller
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1 Answer

4 votes

Answer:

The time interval is
t = 21.30 \ s

Step-by-step explanation:

From the question we are told that

The constant acceleration is
\alpha = 0.029 \ rad / s^2

The displacement is
\theta = 6.58 \ rad

According to the second equation of motion we have that


\theta = w_i* t + (1)/(2) * \alpha t^2

given that the blade started from rest


w_i which is the initial angular velocity is 0

So


\theta = 0 + (1)/(2) * \alpha t^2

=>
t = \sqrt{ (2 * \theta )/(\alpha ) }

substituting values

=>
t = \sqrt{ (2 * 6.58 )/(0.029 ) }

=>
t = 21.30 \ s

User Jeremib
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