Question

A 10.0 mL sample of calcium hydroxide solution required 26.85 mL of 0.225 M hydrochloric acid for neutralization. The balanced equation is:

Answer 1

`C_(base)=0.302M`

Step-by-step explanation:

Hello,

In this case, we can evidence that when calcium hydroxide solution reacts with hydrochloric acid solution, the balanced neutralization reaction turns out:

`2HCl(aq)+Ca(OH)_2\rightarrow CaCl_2(aq)+2H_2O(l)`

Moreover, the concentration of neutralized calcium hydroxide can be computed by using the 2:1 mole ratio between the base and the acid:

`C_(acid)V_(acid)=2*C_(base)V_(base)\\\\C_(base)=(C_(acid)V_(acid))/(2*V_(base)) =(0.225M*26.85mL)/(2*10.0mL)\\ \\C_(base)=0.302M`

Regards.