Question

Find the midpoint of AC.
B (0, a)
C (a, a)
A(0, 0) D (a,0)

Answer 1

The answer is (a/2,a/2)

Explanation:

Fill in 2 then a

In conclusion (a/2,a/2)

Answer 2

`\huge\boxed{\bigg((a)/(2);\ (a)/(2)\bigg)}`

Explanation:

The formula of a midpoint:

`M\bigg((x+1+x+2)/(2);\ (y_1+y_2)/(2)\bigg)`

We have the points

`A(0;\ 0)\to x_1=0;\ y_1=0\\\\C(a;\ a)\to x_2=a;\ y_2=a`

Substitute:

`(x_1+x_2)/(2)=(0+a)/(2)=(a)/(2)\\\\(y_1+y_2)/(2)=(0+a)/(2)=(a)/(2)`