Answer:
The distance of the midpoint of AB = 4 cm
The distance of the midpoint of CD = 28 cm
Explanation:
The given information are;
Segment AD = 36
Point C and point B are points on AD such that AB:BC:CD = 2:3:4
Which gives;
The proportion of AB in AD = 2/(2+3+4) = 2/9
The length of AB = 2/9×36 = 8 cm
The proportion of BC in AD = 3/(2+3+4) = 3/9
The length of AD = 3/9×36 = 12 cm
The proportion of CD in AD = 3/(2+3+4) = 4/9
The length of AD = 4/9×36 = 16 cm
The coordinate of the midpoint of AB = 8/2 = 4 cm from A
The distance of the midpoint of AB = 4 cm
The coordinate of the midpoint of CD = 8 + 12 + 16/2 = 28 cm from A
The distance of the midpoint of CD = 28 cm.