Answer:
The speed of the pendulum when it reaches the lowest point of its path is 2.8 m/s
Step-by-step explanation:
Given;
mass of pendulum, m = 1.5 kg
height of pendulum, h = 0.4 m
At the highest point, the velocity of the pendulum is zero and the kinetic energy is zero, so the total energy at that point is potential energy;
U = mgh
At the lowest point, the height of the pendulum is zero and the potential energy is zero, so the total energy at that point is kinetic energy;
KE = ¹/₂mv²
Apply the principle of conservation of mechanical energy
KE = U
¹/₂mv² = mgh
¹/₂v² = gh
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 0.4)
v = 2.8 m/s
Therefore, the speed of the pendulum when it reaches the lowest path is 2.8 m/s