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Solve the following quadratic equation by completing the square ✓3x^2 + 10x + 7✓3 = 0​

User Cicero
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1 Answer

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√(3)x^2+10x+7√(3)=0\\\\\sqrt3(x^2+(10x)/(√(3))+7)=0\\\\x^2+(10x)/(√(3))+7=0\\\\x^2+(10x)/(√(3))+(25)/(3)-(25)/(3) +7=0\\\\(x+(5)/(√(3)))^2 = (4)/(3)\\\\|x+(5)/(√(3))| = (2)/(√(3))\\\\x_1 = (2)/(√(3))-(5)/(√(3)) = -(3)/(√(3)) = -√(3)\\\\x_2 = -(2)/(√(3))-(5)/(√(3)) = (-7)/(√(3)) = -(-7√(3))/(3)

User DotNetSpartan
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