Answer: y=-(4/3)*x-6
Explanation:
The equation of any straight line is y=a*x+b (1).
So we have to find the coefficients a and b and substitute them to the equation (1).
If the required line is perpendicular to y= (3/4)*x-2 it means that
a= -(4/3) (we have to inverse the fraction 3/4 and put the opposite sign after that. 3/4 has the sign + in front of it so we have to put sign -)
So the equation of required line is y= -(4/3) *x+b .
Now we have to find b. To do that pls remember that the point (-12;10) belongs to the required line y= -(4/3) *x+b . That means:
10=-(4/3)*(-12)+b => 10=16+b => b=-6
So substitute b in equation (1) and get:
y=-(4/3)*x-6