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What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 4x + y + 1 = 0?

4 x + y + 6 = 0
4 x + y - 6 = 0
4 x - y - 6 = 0

User PJvG
by
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1 Answer

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Answer:

The answer is

4x + y - 6 = 0

Explanation:

Equation of a line is y = mx + c

where m is the slope

c is the y intercept

4x + y + 1 = 0

y = - 4x - 1

Comparing with the above formula

Slope / m = - 4

Since the lines are parallel their slope are also the same

That's

Slope of the parallel line is also - 4

Equation of the line using point ( 1 , 2) is

y - 2 = -4(x - 1)

y - 2 = - 4x + 4

4x + y - 2 - 4

We have the final answer as

4x + y - 6 = 0

Hope this helps you

User Michael Rovinsky
by
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