What is the length of a hypotenuse of a triangle if each of its legs is 4 units

Question

asked Apr 23, 2021 200k views

2 Answers

Ivan Koblik · Answer 1 · 2021-04-26T02:54:15+0000

Answer:

Explanation:

Given,

Base ( b ) = 4 units

Perpendicular ( p ) = 4 units

Hypotenuse ( h ) = ?

Now,

Using Pythagoras theorem to find length of hypotenuse:

${h}^(2) = {p}^(2) + {b}^(2)$

Plugging the values

${h}^(2) = {4}^(2) + {4}^(2)$

Evaluate the power

${h}^(2) = 16 + 16$

Calculate the sum

${h}^(2) = 32$

$h = 5.65 \: units$

Hope this helps..

Best regards !!

Roshaw · Answer 2 · 2021-04-28T11:07:04+0000

Answer:

$\boxed{c = 5.7 units}$

Explanation:

Using Pythagorean Theorem:

=>
c^2 = a^2+b^2

Where c is hypotenuse, a is base and b is perpendicular and ( a, b = 4)

=>
c^2 = 4^2+4^2

=>
c^2 = 16+16

=>
c^2 = 32

Taking sqrt on both sides

=> c = 5.7 units