Question

What is the length of a hypotenuse of a triangle if each of its legs is 4 units

Answer 1

5.65 units

Explanation:

Given,

Base ( b ) = 4 units

Perpendicular ( p ) = 4 units

Hypotenuse ( h ) = ?

Now,

Using Pythagoras theorem to find length of hypotenuse:

`{h}^(2) = {p}^(2) + {b}^(2)`

Plugging the values

`{h}^(2) = {4}^(2) + {4}^(2)`

Evaluate the power

`{h}^(2) = 16 + 16`

Calculate the sum

`{h}^(2) = 32`

`h = √(32)`

`h = 5.65 \: units`

Hope this helps..

Best regards !!

Answer 2

`\boxed{c = 5.7 units}`

Explanation:

Using Pythagorean Theorem:

=>
`c^2 = a^2+b^2`

Where c is hypotenuse, a is base and b is perpendicular and ( a, b = 4)

=>
`c^2 = 4^2+4^2`

=>
`c^2 = 16+16`

=>
`c^2 = 32`

Taking sqrt on both sides

=> c = 5.7 units