Question:
The volume of a right circular cone with both diameter and height equal to h is 250/7 cm³.
What is the value of h?
Answer:
A. 5
Explanation:
Given
Solid Shape: Cone
Volume = 250/7
Diameter = Height
Required
Find the height of the cone
Provided that the diameter (D) and the height (h) are equal; This implies that
D = h ------ (1)
Also, Diameter (D) = 2 * Radius (r)
D = 2r
Substitute 2r for D in (1)
2r = h
Multiply both sides by ½
½ * 2r = ½ * h
r = ½h
Volume of a cone is calculated by;
Volume = ⅓πr²h
⅓πr²h = 250/7
Substitute ½h for r
![(1)/(3) * \pi * ((1)/(2)h)^2 * h = (250)/(7)](https://img.qammunity.org/2021/formulas/mathematics/high-school/mo97yoy181dhdz3ae9zjltdvciih4h4fc0.png)
Take π as 22/7, the expression becomes
![(1)/(3) * (22)/(7) * ((1)/(2)h)^2 * h = (250)/(7)](https://img.qammunity.org/2021/formulas/mathematics/high-school/sq8j5va301f1ge6ffwdib66xt6qj7dn42b.png)
Open the bracket
![(1)/(3) * (22)/(7) * (1)/(4)h^2 * h = (250)/(7)](https://img.qammunity.org/2021/formulas/mathematics/high-school/sqja8j923al0z7xzfdjs0d25bn2yr90wmt.png)
Multiply both sides by 7
![7 * (1)/(3) * (22)/(7) * (1)/(4)h^2 * h = (250)/(7) * 7](https://img.qammunity.org/2021/formulas/mathematics/high-school/yfmyvnd9mzc0nock1rft04cnrtyswvf62k.png)
![(1)/(3) * 22 * (1)/(4)h^2 * h = 250](https://img.qammunity.org/2021/formulas/mathematics/high-school/td9psk1dxlpdm4f74v4qrmpctwe1yu55vd.png)
Multiply both sides by 3
![3 * (1)/(3) * 22 * (1)/(4)h^2 * h = 250 * 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/128bkto2fsrodbelthyylh5obgyqgpjzic.png)
![22 * (1)/(4)h^2 * h = 750](https://img.qammunity.org/2021/formulas/mathematics/high-school/2ogcnh6z6uak6k8stagvrabs1i518uj958.png)
Multiply both sides by 4
![4 * 22 * (1)/(4)h^2 * h = 750 * 4](https://img.qammunity.org/2021/formulas/mathematics/high-school/3n7u0h8ucfxvmwkhqqyw5zsj1w32j6pob3.png)
![22 * h^2 * h = 3000](https://img.qammunity.org/2021/formulas/mathematics/high-school/q3b70qnlz6313r3z1phbt1vcy8hij68k52.png)
![22 * h^3 = 3000](https://img.qammunity.org/2021/formulas/mathematics/high-school/ucjb3w0i37gjj6jwajlv8iehyjsw8r6rko.png)
Divide both sides by 22
![h^3 = (3000)/(22)](https://img.qammunity.org/2021/formulas/mathematics/high-school/d6cadmqdehggaohrmsfnpi5e5k5v1779vj.png)
![h^3 = 136.36](https://img.qammunity.org/2021/formulas/mathematics/high-school/yurnqg3kjn9a4ib9q8thq5nx3tzbig9nds.png)
Take cube root of both sides
![h = \sqrt[3]{136.36}](https://img.qammunity.org/2021/formulas/mathematics/high-school/e0e5z2t0jy0p1g7pd32ov6f5m6f7iapj5o.png)
![h = 5.15](https://img.qammunity.org/2021/formulas/mathematics/high-school/j27dlcmz5l3glvrh1vukyynpyot52mcklq.png)
(Approximated)