Answer:
The temperature of the filament when the flashlight is on is 2020 °C.
Step-by-step explanation:
The resistivity varies linearly with temperature:
(1)
Where:
T: is the temperature of the filament when the flashlight is on=?
T₀: is the initial temperature = 20 °C
α: is the temperature coefficient of resistance = 0.0045 °C⁻¹
R₀: is the resistance at T₀ = 1.5 Ω
When V = 3.0 V, R is:

By solving equation (1) for T we have:

Therefore, the temperature of the filament when the flashlight is on is 2020 °C.
I hope it helps you!