Answer:
ΔABC is a right triangle
length of the concession stand = 42.4 ft (nearest tenth)
Explanation:
Given:
- Side length of square A = 30 ft
- Side length of square B = 40 ft
- Side length of square C = 50 ft
We can use Pythagoras' Theorem to prove if ΔABC is a right triangle.
Pythagoras' Theorem: a² + b² = c² (where a and b are the legs, and c is the hypotenuse of a right triangle)
Given:
- a = side length of square A = 30
- b = side length of square B = 40
- c = side length of square C = 50
⇒ a² + b² = c²
⇒ 30² + 40² = 50²
⇒ 900 + 1600 = 2500
⇒ 2500 = 2500
Therefore, ΔABC is a right triangle
To find the diagonal of square A, use Pythagoras' Theorem:
Given:
- a = side length of square A = 30
- b = side length of square A = 30
- c = diagonal of square A
⇒ a² + b² = c²
⇒ 30² + 30² = c²
⇒ 900 + 900 = c²
⇒ c² = 1800
⇒ c = √(1800)
⇒ c = 42.42640687
Therefore, the length of the concession stand (diagonal of square A) is 42.4 ft (nearest tenth)