Answer:
539.3mmHg of H₂
179.7mmHg of N₂
Step-by-step explanation:
Ammonia, NH₃, reacts completely producing N₂ and H₂ thus:
2 NH₃ → N₂ + 3H₂
That means there are produced 4 moles of gases and 3 are of H₂ and 1 of N₂
Total pressure (Sum of pressures of N₂ and H₂) is 719mmHg. 3 parts are of H₂ and 1 of H₂
Thus, partial pressures of the products after reaction are:
719mmHg ₓ (3 H₂ / 4) = 539.3mmHg of H₂
719mmHg ₓ (1 N₂ / 4) = 179.7mmHg of N₂