Question

How many Real solutions

Answer 1

The right answer for this would be A

Answer 2

A. 2 real roots: (2, 7) and (1, 4).

Explanation:

y = x^2 + 3

y = 3x + 1

So equating the right sides:

x^2 + 3 = 3x + 1

x^2 - 3x + 2 = 0

(x - 2)(x - 1) = 0

So there are 2 roots.

They are x = 2 , y = 3(2) + 1 = 7 and

x = 1, y = 3(1) +1 = 4.