Question

A simple random sample of 49 students at UH indicated that 85% of them are involved in some type club. Find the 99% confidence interval that estimates the true proportion of UH students that are involved in a club

Answer 1

0.85 ± 0.1314

Explanation:

P*=0.85

n=49

z for 99% confidence interval = 2.576

The estimates the true proportion of UH students that are involved in a club (99% confidence interval) =

`0.85\pm 2.576* \sqrt{(0.85(1-0.85))/(49) } \\\\= 0.85\pm 0.1314`

=0.9814, 0.7186

We are 99% confident that the true proportion of UH students that are involved in a club is 0.85 with a margin of error of 0.1314.