Question

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Answer 1

a. u = 19

b. t = 6

c. a = 2

Explanation:

a. Given,

v = 34 , a = 5 , t = 3

`v = u + at`

plugging the values:

`34 = u + 5 * 3`

Calculate the product

`34 = u + 15`

Move 'u' to L.H.S and change its sign

`- u + 34 = 15`

Move constant to RHS and change its sign

`- u = 15 - 34`

Calculate

`- u = - 19`

The difference sign (-) will be cancelled in both sides:

`u = 19`

b. Given,

v = 50 , u = 20 , a = 5

`v = u + at`

plugging the values

`50 = 20 + 5 * t`

`50 = 20 + 5t`

Move 5t to L.H.S and change its sign.

Similarly, Move 50 to R.H.S and change its sign

`- 5t = 20 - 50`

Calculate

`- 5t = - 30`

The difference sign (-) will be cancelled in both sides

`5t = 30`

Divide both sides of the equation by 5

`(5t)/(5) = (30)/(5)`

Calculate

`t = 6`

c. Given,

v = 22 , u = 8 , t = 7

`v = u + at`

plugging the values

`22 = 8 + a * 7`

`22 = 8 + 7a`

Move 7a to LHS and change its sign

Similarly, Move constant to R.H.S and change its sign

`- 7a = 8 - 22`

Calculate

`- 7a = - 14`

The difference sign (-) will be cancelled in both sides

`7a = 14`

Divide both sides of the equation by 7

`(7a)/(7) = (14)/(7)`

Calculate

`a = 2`

Hope this helps...

Good luck on your assignment..