Question

Find the 61st term of the following arithmetic sequence.
15, 24, 33, 42,

Answer 1

The answer is

555

Explanation:

For an nth term in an arithmetic sequence

`U(n) = a + (n - 1)d`

where n is the number of terms

a is the first term

d is the common difference

From the question

a = 15

d = 24 - 15 = 9

n = 61

So the 61st term of the arithmetic sequence is

U(61) = 15 + (61-1)9

= 15 + 9(60)

= 15 + 540

= 555

Hope this helps you.