Question

Solve the quadractic equation 3x^2-5x-7=0

Answer 1

Hello!

`\sf 3x^2-5x-7=0\\\\x = \frac{-b\±\sqrt{b^(2)-4ac } }{2a} \\\\\\x = \frac{-(-5)\±\sqrt{(-5)^(2)-4 ~*~3~*~ (-7) } }{2~*~ (-5)} \\\\\\\boxed{\sf x = (5\±√(109) )/(-10)}`