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Solve the quadractic equation 3x^2-5x-7=0

User Ductran
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1 Answer

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Hello!


\sf 3x^2-5x-7=0\\\\x = \frac{-b\±\sqrt{b^(2)-4ac } }{2a} \\\\\\x = \frac{-(-5)\±\sqrt{(-5)^(2)-4 ~*~3~*~ (-7) } }{2~*~ (-5)} \\\\\\\boxed{\sf x = (5\±√(109) )/(-10)}

User LeonardBlunderbuss
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